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0=-4.9x^2+2x+10
We move all terms to the left:
0-(-4.9x^2+2x+10)=0
We add all the numbers together, and all the variables
-(-4.9x^2+2x+10)=0
We get rid of parentheses
4.9x^2-2x-10=0
a = 4.9; b = -2; c = -10;
Δ = b2-4ac
Δ = -22-4·4.9·(-10)
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10\sqrt{2}}{2*4.9}=\frac{2-10\sqrt{2}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10\sqrt{2}}{2*4.9}=\frac{2+10\sqrt{2}}{9.8} $
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